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Migration and Other Snowflake Services
Get Up and Running with Snowpark
Using the SnowConvert Trial
Build a Cross-Platform Object Inventory
In C# a foreach variable can't be assignable, so to avoid a compilation error, the line must be commented. In VB.Net the iteration variable can be assigned so, this restriction is not applied.
Check the logic of the original VB6 function. In some cases the nothing assignation to the iteration variable is a way to stop the cycle. If this is the case use the break statement instead.For the given example, just remove the commented line and the EWI.
Public Function TestCommentedLines(ByVal P() As String) As Integer Dim S Dim Count As Integer For Each S In P If Not S IsNothing Then MsgBox(S) Count = Count + 1 S = Nothing End If Next S TestCommentedLines = Count End Function
public int TestCommentedLines( string[] P) { int Count = 0; foreach (string S in P) { if (S != null) { MessageBox.Show(S, Application.ProductName); Count++; //UPGRADE_NOTE: (2041) The following line was commented. //S = null; } } return Count; }
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